CCE progress card software

 

CCE GRADING SOFTWARE

🌸🌸A unique and Excellent CCE grading software exclusively designed for High schools.

This CCE software helps in calculating class  wise analysis , Sub wise analysis , Progress cards, Consolidate reports, School Grading analysis and much more. This software reduces tedious process of report card preparation.

  

👉 CLICK HERE TO DOWNLOAD SOFTWARE for  V-X classes exclusively for GURUKULAM SCHOOLS for class strength 80 @ 40  each section . 

  👉 CLICK HERE TO DOWNLOAD SOFTWARE  for VI-X classes exclusively for ALL HIGH SCHOOLS for maximum 100 STRENGTH @ 50 each section.

Note: As It is a macro enabled program you must enable macros option in your computer to run the program.

                                        
WAY TO ENABLE MACROS.

👉1.CLICK ON FILE MENU> CLICK  OPTIONS > TRUST CENTER  > TRUST CENTER SETTINGS > MACROS SETTINGS > SELECT ENABLE OPTION. (Permanent way)

Contact @ 7680089005 for queries. 

Updated on 26/08/2023

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TSTEACHERS BADI

✍ 4×3=12 is 4+4+4=12  or 3+3+3+3=12 ?

👉 Explaination

 ✍Misconception

4×3=12 read as 4 3times =12. (4+4+4)
Similarly 4×2=8 read as 4 2times=8. (4+4)
If so then 4×0=0 should be read as 4 0times=0.(?)
Here it is not possible to write 4 zero times. Merely its impossible. So 4×3=12 is not correct to show as 4+4+4=12.

✍Reality

4×3=12 read as 4times 3 =12.(3+3+3+3)
Similarly 4×2=8 read as 4times 2 =8.(2+2+2+2).
Similarly 4×0=0 read as 4times 0 =0.(0+0+0+0)
Here we can show 0 to any number of times.

*************************
In Simple way

4×5=20 (4+4+4+4+4)
4×4=16 (4+4+4+4)
4×3=12 (4+4+4)
4×2=8 (4+4)
4×1=4 (4)
4×0=0 (? ) how can we show 4 zero times.?
So its wrong.

4×5=20 (5+5+5+5)
4×4=16 (4+4+4+4)
4×3=12 (3+3+3+3)
4×2=8 (2+2+2+2)
4×1=4 (1+1+1+1)
4×0=0(0+0+0+0)
We can show 0 to 4 times equals to 0.
*************************************

✍ *Why is -(-a)=a?*

We know that any number plus its opposite is zero. So let's begin there:

• 1 + (-1) = 0

Now we multiply both sides by (-1). On the right-hand side, zero times (-1) is zero.
(-1) [ 1 + (-1) ] = 0

Now
(-1)(1) + (-1)(-1) = 0

But (-1)(1) = (-1) because of identity (any number times 1 is itself), so

(-1) + (-1)(-1) = 0
Now we add one to both sides and simplify
1 + (-1) + (-1)(-1) = 1
(-1)(-1) = 1

******************************
*Another simple way*

-A+A=0   ------------1
Let -A =B assumption
Now form equation 1
B+A=0
Move B to right hand side
A= -B
Now substitute B value
A=-(-A)
********************************
If any viewer finds the proof is wrong pls comment. Even they can send the correct proof to my mail.I will post it with their name.
Thank you

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